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x^2-0.08x-0.08=0
a = 1; b = -0.08; c = -0.08;
Δ = b2-4ac
Δ = -0.082-4·1·(-0.08)
Δ = 0.3264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.08)-\sqrt{0.3264}}{2*1}=\frac{0.08-\sqrt{0.3264}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.08)+\sqrt{0.3264}}{2*1}=\frac{0.08+\sqrt{0.3264}}{2} $
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